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9n^2+18n-7=0
a = 9; b = 18; c = -7;
Δ = b2-4ac
Δ = 182-4·9·(-7)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-24}{2*9}=\frac{-42}{18} =-2+1/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+24}{2*9}=\frac{6}{18} =1/3 $
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